3Li6+0n1⟶2He4+1H3 1H2+1H3⟶2He4+0n1 _____________________ 3Li6+1H2⟶2(2He4) _____________________ Energy released in process Q=∆mc2 Q=[M(Li)+M(1H2)−2×M(2He4)]×931.5MeV Q=[6.01690+2.01471−2×4.00388]×931.5MeV Q=22.216MeV Q=22.22MeV