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JEE Main Physics Class 12 Atoms and Nuclei Part 3 Questions
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© examsnet.com
Question : 6
Total: 69
The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is :
[6 Apr 2024 Shift 1]
4
:
1
1
:
2
1
:
4
2
:
1
Validate
Solution:
👈: Video Solution
1
λ
=
Rz
2
(
1
n
1
2
−
1
n
2
2
)
1
λ
L
1
=
Rz
2
(
1
1
2
)
1
λ
B
=
Rz
2
(
1
2
2
)
λ
B
λ
L
=
4
:
1
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