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JEE Main Physics Class 12 Current Electricity Part 1 Questions
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© examsnet.com
Question : 14
Total: 100
In the experimental set up of metre bridge shown in the figure, the null point is obtaine data distance of 40 cm from A. If a 10 W resistor is connected in series with
R
1
, the null point shifts by 10 cm. The resistance that should be connected in parallel with
(
R
1
+
10
)
Ω
such that the null point shifts back to its initial position is :
[11 Jan. 2019 II]
20 Ω
40 Ω
60 Ω
30 Ω
Validate
Solution:
Initially at null deflection
R
1
R
2
=
2
3
...(i)
Finally at null deflection, when null point is shifted
R
1
+
10
R
2
=
1
⇒
R
1
+
10
=
R
2
......(ii)
Solving equations (i) and (ii) we get
2
R
2
3
+
10
=
R
2
10
=
R
2
3
⇒
R
2
=
30
Ω
&
R
1
=
20
Ω
Now if required resistance is
R
then
30
×
R
30
+
R
30
=
2
3
R
=
60
Ω
© examsnet.com
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