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JEE Main Physics Class 12 Current Electricity Part 1 Questions
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© examsnet.com
Question : 16
Total: 100
The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as
R
1
has the colour code (Orange, Red, Brown). The resistors
R
2
and
R
4
are
80
Ω
and
40
Ω
, respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as
R
3
,
would be:
[10 Jan. 2019 II]
Brown, Blue, Brown
Brown, Blue, Black
Red, Green, Brown
Grey, Black, Brown
Validate
Solution:
Given, colour code of resistance,
R
1
=
Orange, Red and Brown
∴
R
1
=
32
×
10
=
320
using balanced wheatstone bridge principle,
R
1
R
3
=
R
2
R
4
⇒
320
R
3
=
80
40
∴
R
3
=
160
i.e. colour code for
R
3
Brown, Blue and Brown
© examsnet.com
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