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JEE Main Physics Class 12 Current Electricity Part 1 Questions
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© examsnet.com
Question : 26
Total: 100
In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :
[2017]
C
E
r
2
(
r
+
r
2
)
C
E
r
1
(
r
1
+
r
)
C
E
C
E
r
1
(
r
2
+
r
)
Validate
Solution:
In steady state, flow fo current through capacitor will be be zero. Current through the circuit,
i
=
E
r
+
r
2
Potential difference through capacitor
V
c
=
Q
C
=
E
−
i
r
=
E
−
(
E
r
+
r
2
)
r
∴
Q
=
C
E
r
2
r
+
r
2
© examsnet.com
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