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JEE Main Physics Class 12 Current Electricity Part 1 Questions
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© examsnet.com
Question : 31
Total: 100
In a meter bridge experiment resistances are connected as shown in the figure. Initially resistance P = 4 Ω and the neutral point N is at 60 cm from A. Now an unknown resistance R is connected in series to P and the new position of the neutral point is at 80 cm from A. The value of unknown resistance R is :
[Online April 9, 2017]
33
5
Ω
6
Ω
7
Ω
20
3
Ω
Validate
Solution:
In balance position of bridge,
P
Q
=
l
(
100
−
l
)
Initially neutral position is
60
c
m
.
from
A
,
so
4
60
=
Q
40
⇒
Q
=
16
6
=
8
3
Ω
Now, when unknown resistance
R
is connected in series to P, neutral point is
80
c
m
from A then,
4
+
R
80
=
Q
20
4
+
R
80
=
8
60
R
=
64
6
−
4
=
64
−
24
6
=
40
6
Ω
Hence, the value of unknown resistance
R
is
=
20
3
Ω
© examsnet.com
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