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JEE Main Physics Class 12 Current Electricity Part 2 Questions
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© examsnet.com
Question : 21
Total: 100
The resistance of a conductor at
15
°
C
is
16
Ω
and at
100
°
C
is
20
Ω
. What will be the temperature coefficient of resistance of the conductor?
[27 Jul 2021 Shift 2]
0.010
°
C
−
1
0.033
°
C
−
1
0.003
°
C
−
1
0.042
°
C
−
1
Validate
Solution:
16
=
R
0
[
1
+
α
(
15
−
T
o
)
]
20
=
R
0
[
1
+
α
(
100
−
T
o
)
]
Assuming
T
o
=
0
°
C
, as a general convention.
⇒
16
20
=
1
+
α
×
15
1
+
α
×
100
⇒
α
=
0.003
°
C
−
1
© examsnet.com
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