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JEE Main Physics Class 12 Current Electricity Part 2 Questions
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© examsnet.com
Question : 3
Total: 100
In the given circuit 'a' is an arbitrary constant. The value of
m
for which the equivalent circuit resistance is minimum, will be
√
x
2
. The value of
x
is _____
[27-Jun-2022-Shift-2]
Your Answer:
Validate
Solution:
R
n
e
t
=
m
a
3
+
a
2
m
=
a
[
m
3
+
1
2
m
−
2
√
6
+
2
√
6
]
=
a
[
(
√
m
3
−
1
√
2
m
)
2
+
√
2
3
]
This will be minimum when
√
m
3
=
1
√
2
m
or
m
=
√
3
2
so
x
=
3
© examsnet.com
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