Using Kirchoff's loop law in loop ABCD −5i2−10(i1+i2)−2i2+20=0 ⇒−10i1−17i2+20=0 ......(i) Using Kirchoff's loop law in loop BEFC ⇒−10+4i1+10(i1+i2)=0 ⇒14i1+10i2+10=0 .......(ii) Multiplying equation (i) by 10 , we have (10i1+17i2=20)×10 ⇒100i1−170i2=200 .....(iii) Multiplying equation (ii) by 17, we have (14i1+10i2=10)×17 ⇒238i1−170i2=170 ......(iv) On solving equations (iii) and (iv), we get −138i1=30⇒i1=−
30
138
=−0.217 i1 is negative it means current flows from positive to negative terminal.