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JEE Main Physics Class 12 Current Electricity Part 2 Questions
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© examsnet.com
Question : 94
Total: 100
In the given circuit the internal resistance of the
18
V
cell is negligible. If
R
1
=
400
Ω
,
R
3
=
100
Ω
and
R
4
=
500
Ω
and the reading of an ideal voltmeter across
R
4
is
5
V
then the value of
R
2
will be:
[9 Jan. 2019 II]
300 Ω
450 Ω
550 Ω
230 Ω
Validate
Solution:
Across
R
4
reading of voltmeter,
V
4
=
5
V
Current,
i
4
=
V
4
R
4
=
0.01
A
V
3
=
i
1
R
3
=
1
V
V
3
+
V
4
=
6
V
=
V
2
V
1
+
V
3
+
V
4
=
18
V
⇒
V
1
=
12
V
i
=
V
1
R
1
=
0.03
A
i
=
i
1
+
i
2
⇒
i
2
=
i
−
i
,
=
0.03
−
0.01
A
=
0.02
A
∴
R
2
=
V
2
i
2
=
6
0.02
=
300
Ω
© examsnet.com
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