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JEE Main Physics Class 12 Current Electricity Part 4 Questions
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© examsnet.com
Question : 31
Total: 31
In the given circuit, the current flowing through the resistance
20
Ω
is
0.3
A
, while the ammeter reads 0.9 A. The value of
R
1
is_____
Ω
.
[29-Jan-2024 Shift 2]
Your Answer:
Validate
Solution:
👈: Video Solution
Given,
i
1
=
0.3
A
,
i
1
+
i
2
+
i
3
=
0.9
A
So,
V
A
B
=
i
1
×
20
Ω
=
20
×
0.3
V
=
6
V
i
2
=
6
V
15
Ω
=
2
5
A
i
1
+
i
2
+
i
3
=
9
10
A
3
10
+
2
5
+
i
3
=
9
10
7
10
+
i
3
=
9
10
i
3
=
0.2
A
So,
i
3
×
R
1
=
6
V
(
0.2
)
R
1
=
6
R
1
=
6
0.2
=
30
Ω
© examsnet.com
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