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Test Index
JEE Main Physics Class 12 Dual Nature of Matter and Radiation Part 1 Questions
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© examsnet.com
Question : 32
Total: 100
Particle
A
of mass
m
A
=
m
2
moving along the
x
-axis with velocity
v
0
collides elastically with another particle
B
at rest having mass
m
B
=
m
3
.
If both particles move along the
x
-axis after the collision, the change
Δ
λ
in de-Broglie wavelength of particle
A
,
in terms of its de-Broglie wavelength
(
λ
0
)
before collision is :
[Sep. 04, 2020 (I)]
Δ
λ
=
3
2
λ
0
Δ
λ
=
5
2
λ
0
Δ
λ
=
2
λ
0
Δ
λ
=
4
λ
0
Validate
Solution:
Applying momentum conservation
m
2
×
V
0
+
m
3
×
(
0
)
=
m
2
V
A
+
m
3
V
B
=
V
0
2
=
V
A
2
+
V
B
3
.....(i)
Since, collision is elastic
e
=
1
=
V
B
−
V
A
V
0
⇒
V
0
=
V
B
−
V
A
........(ii)
On solving equations (i) and (ii) :
V
A
=
V
0
5
Now, de-Broglie wavelength of
A
before collision :
λ
)
0
=
h
m
A
V
0
=
h
(
m
2
)
V
0
⇒
λ
0
=
2
h
m
V
0
Final de-Broglie wavelength :
λ
f
=
h
m
A
V
0
=
h
m
2
×
V
0
5
⇒
λ
f
=
10
h
m
V
0
∴
Δ
λ
=
λ
f
−
λ
0
=
10
h
m
V
0
−
2
h
m
V
0
⇒
Δ
λ
=
8
h
m
v
0
⇒
Δ
λ
=
4
×
2
h
m
v
0
∴
Δ
λ
=
4
λ
0
© examsnet.com
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