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JEE Main Physics Class 12 Electromagnetic Induction Questions
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© examsnet.com
Question : 4
Total: 120
In a coil, the current changes form
−
2
A
to
+
2
A
in
0.2
s
and induces an emf of
0.1
V
. The selfinductance of the coil is :
[6 Apr 2024 Shift 2]
5
mH
1
mH
2.5
mH
4
mH
Validate
Solution:
👈: Video Solution
(
Emf
)
induced
=
−
L
di
dt
In magnitude form,
|
Emf
ind
|
=
|
(
−
)
L
di
dt
|
⇒
0.1
=
(
L
)
[
+
2
−
(
−
2
)
]
0.2
⇒
L
=
0.1
×
0.2
4
=
5
mH
© examsnet.com
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