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JEE Main Physics Class 12 Electromagnetic Induction Questions
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© examsnet.com
Question : 50
Total: 120
Two coils of self inductance
L
1
and
L
2
are connected in series combination having mutual inductance of the coils as
M
. The equivalent self inductance of the combination will be :
[26-Jun-2022-Shift-2]
1
L
1
+
1
L
2
+
1
M
L
1
+
L
2
+
M
L
1
+
L
2
+
2
M
L
1
+
L
2
−
2
M
Validate
Solution:
Self inductances are in series but their mutual inductances are linked oppositely so equivalent self inductance
L
=
L
1
+
L
2
−
M
−
M
=
L
1
+
L
2
−
2
M
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