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JEE Main Physics Class 12 Electronic Devices Part 1 Questions
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© examsnet.com
Question : 39
Total: 99
In a common emitter configuration with suitable bias, it is given than
R
L
is the load resistance and
R
B
E
is small signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given, respectively, by:
(
β
is current gain,
I
B
,
I
C
,
I
E
are respectively base, collector and emitter currents:)
[Online April 15,2018]
β
R
L
R
B
E
,
Δ
I
E
Δ
I
B
,
β
2
R
L
R
B
E
β
2
R
L
R
B
E
,
Δ
I
C
Δ
I
B
,
β
R
L
R
B
E
β
2
R
L
R
B
E
,
Δ
I
C
Δ
I
E
,
β
2
R
L
R
B
E
β
R
L
R
B
E
,
Δ
I
C
Δ
I
B
,
β
2
R
L
R
B
E
Validate
Solution:
Curent gain
β
=
Δ
I
C
I
B
Voltage gain
A
v
=
Current gain
×
Resistance gain
=
β
R
L
R
B
E
Power gain
A
p
=
(
Current gain
)
2
×
Resistance gain
=
β
2
R
L
R
B
E
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