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JEE Main Physics Class 12 Electronic Devices Part 1 Questions
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© examsnet.com
Question : 60
Total: 99
A Zener diode is connected to a battery and a load as show below:
The currents, I,
I
Z
and
I
L
are respectively.
[Online April 11, 2014]
15 mA, 5 mA, 10 mA
15 mA, 7.5 mA, 7.5 mA
12.5 mA, 5 mA, 7.5 mA
12.5 mA, 7.5 mA, 5 mA
Validate
Solution:
Here,
R
=
4
k
Ω
=
4
×
10
3
Ω
V
i
=
60
V
Zener voltage
V
z
=
10
V
R
L
=
2
k
Ω
=
2
×
10
3
Ω
Load current,
I
L
=
V
Z
R
L
=
10
2
×
10
3
=
5
m
A
Current through
R
,
I
=
V
i
−
V
Z
R
=
60
−
10
4
×
10
3
=
50
4
×
10
3
=
12.5
m
A
Fom circuit diagram,
I
=
I
Z
+
I
L
⇒
12.5
=
I
Z
+
5
⇒
I
Z
=
12.5
−
5
=
7.5
m
A
© examsnet.com
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