Test Index

JEE Main Physics Class 12 Electronic Devices Part 1 Questions

© examsnet.com

Question : 7

Total: 99

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is: Planck's constant, h=6.63×10−34J.s
Speed of light, c=3×108m∕s

[Sep. 03,2020 (II)]

1.1 eV
2.0 eV
1.5 eV
3.1 eV

Go to Question:

Prev Question

Next Question