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JEE Main Physics Class 12 Electronic Devices Part 2 Questions
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© examsnet.com
Question : 6
Total: 111
The acceptor level of a p-type semiconductor is
6
eV
. The maximum wavelength of light which can create a hole would be : Given
hc
=
1242
eV
nm
.
[6 Apr 2024 Shift 2]
407
nm
414
nm
207
nm
103.5
nm
Validate
Solution:
👈: Video Solution
Energy
=
hc
λ
E
=
1240
λ
(
nm
)
eV
6
=
1240
λ
(
nm
)
λ
=
1240
6
=
207
nm
© examsnet.com
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