JEE Main Physics Class 12 Electrostatic Potential and Capacitance Part 1 Questions

When two capacitors with capacitance C1 and C2 at potential V1 and V2 connected to each other by wire, charge begins to flow from higher to lower potential till they acquire common potential. Here, some loss of energy takes place which is given by.
Heat loss, H=

C1C2

2(C1+C2)

(V1−V2)2
In the equation, put V2=0,V1=V0
C1=C,C2=

C

2

Loss of heat =

C× C 2

2(C+ C 2 )

(V0−0)2 =

C

6

V02
H=

1

6

CV02