The simplified circuit of the circuit given in question as follows:
The equivalent capacitance between C&D capacitors of 2µF,5µF and 5µF are in parallel. ∴CCD=2+5+5=12µF(because In parallel groupingCeq=C1+C2+.....+Cn) Similarly equivalent capacitance between E&BCEB=4+2=6µF Now equivalent capacitance between A&B