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JEE Main Physics Class 12 Electrostatic Potential and Capacitance Part 1 Questions

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Question : 6

Total: 100

A 10 µF capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is :

[Sep. 02, 2020 (II)]

15 µF
30 µF
20 µF
10 µF

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