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JEE Main Physics Class 12 Magnetism and Matter Questions
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© examsnet.com
Question : 54
Total: 80
A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their magnetic moment parallel to their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder are
T
h
and
T
c
respectively, then:
[10 Jan. 2019 II]
T
h
=
T
c
T
h
=
2
T
c
T
h
=
1.5
T
T
h
=
0.5
T
c
Validate
Solution:
Using, time /oscillation period,
T
=
2
π
√
I
M
B
Where,
M
=
magnetic moment, I moment of inertia and
B
=
magnetic field
T
h
=
2
π
√
m
R
2
(
2
M
B
)
T
c
=
2
π
√
1
∕
2
m
R
2
M
B
Clearly,
T
h
=
T
c
© examsnet.com
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