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JEE Main Physics Class 12 Magnetism and Matter Questions
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© examsnet.com
Question : 60
Total: 80
A fighter plane of length
20
m
, wing span (distance from tip of one wing to the tip of the other wing) of
15
m
and height
5
m
is lying towards east over Delhi. Its speed is
240
m
s
−
1
. The earth's magnetic field over Delhi is
5
×
10
−
5
T
with the declination angle
∼
0
°
and dip of
θ
such that
sin
θ
=
2
3
.
If the voltage developed is
V
B
between the lower and upper side of the plane and
V
W
between the tips of the wings then
V
B
and
V
W
are close to :
[Online April 10, 2016]
V
B
=
40
m
V
;
V
W
=
135
mV with left side of pilot at higher voltage
V
B
=
45
m
V
;
V
W
=
120
mV with right side of pilot at higher voltage
V
B
=
40
m
V
;
V
W
=
135
mV with right side of pilot at higher voltage
V
B
=
45
m
V
;
V
W
=
120
mV with left side of pilot at higher voltage
Validate
Solution:
V
B
=
V
B
H
l
=
240
×
5
×
10
−
5
cos
(
θ
)
×
5
=
44.7
m
v
By right hand rule, the charge moves to the left of pilot.
© examsnet.com
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