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Test Index
JEE Main Physics Class 12 Magnetism and Matter Questions
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Question : 62
Total: 80
A short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East – West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in
A
m
2
is close to:
(
Given
µ
0
4
π
=
10
−
7
in SI units and
B
H
= Horizontal component of earth’s magnetic field
=
3.6
×
10
–
5
tesla)
[Online April 11, 2015]
14.6
19.4
9.7
4.9
Validate
Solution:
Here,
r
=
30
c
m
=
0.3
c
m
we know
µ
0
M
4
π
r
3
=
B
H
=
3.6
×
10
−
5
⇒
M
=
3.6
×
10
−
5
10
−
7
(
0.3
)
3
Hence,
M
=
9.7
A
m
2
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