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Test Index
JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 31
Total: 100
A current of
1
A
is flowing on the sides of an equilateral triangle of side
4.5
×
10
−
2
m
. The magnetic field at the centre of the triangle will be:
[Online April 15, 2018]
4
×
10
−
5
W
b
∕
m
2
Zero
2
×
10
−
5
W
b
∕
m
2
8
×
10
−
5
W
b
∕
m
2
Validate
Solution:
Here, side of the triangle,
l
=
4.5
×
10
−
2
m
,
current,
I
=
1
A
magnetic field at the centre of the triangle '
O
'
B
=
?
From figure,
tan
60
°
=
√
3
=
1
2
d
⇒
d
=
l
2
√
3
=
(
4.5
×
10
−
2
2
√
3
)
m
Magnetic field,
B
=
µ
0
i
4
π
d
(
cos
θ
1
+
cos
θ
2
)
Putting value of
mu
=
4
π
×
10
−
7
and
θ
1
and
θ
2
we will get
B
=
4
×
10
−
5
W
b
∕
m
2
© examsnet.com
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