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JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 34
Total: 100
A galvanometer with its coil resistance
25
Ω
requires a current of
1
m
A
for its full deflection. In order to construct an ammeter to read up to a current of
2
A
, the approximate value of the shunt resistance should be
[Online April 16,2018]
2.5
×
10
−
2
Ω
1.25
×
10
−
3
Ω
2.5
×
10
−
3
Ω
1.25
×
10
−
2
Ω
Validate
Solution:
According to question, current through galvanometer,
I
a
=
1
m
A
Current through shunt
(
I
−
I
o
)
=
2
A
Galvanometer resistance
R
g
=
25
Ω
Resistance of shunt,
S
=
?
I
0
R
0
=
(
I
−
I
g
)
S
⇒
S
=
10
−
3
×
25
2
S
≃
1.25
×
10
−
2
Ω
© examsnet.com
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