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JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 36
Total: 100
In a certain region static electric and magnetic fields exist. The magnetic field is given by
→
B
=
B
0
(
^
i
+
2
^
j
−
4
^
k
)
.
If a test charge moving with a velocity
→
v
=
v
0
(
3
^
i
−
^
j
+
2
^
k
)
experiences no force in that region, then the electric field in the region, in SI units, is :
[Online April 8, 2017]
→
E
=
−
v
0
B
0
(
3
^
i
−
2
^
j
−
4
^
k
)
→
E
=
−
v
0
B
0
(
^
i
+
^
j
+
7
^
k
)
→
E
=
v
0
B
0
(
14
^
j
+
7
^
k
)
→
E
=
−
v
0
B
0
(
14
^
j
+
7
^
k
)
Validate
Solution:
According to question, as the test charge experiences no net force in that region i.e., sum of electric force
(
F
e
e
=
q
→
E
)
and magnetic forces
[
F
m
=
q
(
→
v
×
→
B
]
will be zero.
Hence,
F
e
+
F
m
=
0
F
e
=
−
q
(
→
v
×
→
B
)
=
−
B
0
v
0
[
(
3
^
i
−
^
j
+
2
^
k
)
×
(
^
i
+
2
^
j
−
4
^
k
)
]
=
−
B
0
v
0
(
14
^
j
+
7
^
k
)
© examsnet.com
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