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JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 49
Total: 100
A wire carrying current I is tied between points
P
and
Q
and is in the shape of a circular arc of radius
R
due to a uniform magnetic field
B
(perpendicular to the plane of the paper, shown by
x
x
x
) in the vicinity of the wire. If the wire subtends an angle
2
θ
0
at the centre of the circle (of which it forms an arc) then the tension in the wire is :
[Online April 11, 2015]
I
B
R
2
sin
θ
0
I
B
R
θ
0
sin
θ
0
IBR
I
B
R
sin
θ
0
Validate
Solution:
For small arc length
2
T
sin
θ
=
BIR
2
θ
(
As
F
=
B
I
L
and
L
=
R
Z
θ
)
T
=
B
I
R
© examsnet.com
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