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JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 6
Total: 100
A thin ring of
10
c
m
radius carries a uniformly distributed charge. The ring rotates at a constant angular speed of 40 À rad
s
−
1
about its axis, perpendicular to its plane. If the magnetic field at its centre is
3.8
×
10
−
9
T
, then the charge carried by the ring is close to
(
µ
0
=
4
π
×
10
−
7
N
∕
A
2
)
.
[12 April 2019, I]
2
×
10
−
6
C
3
×
10
−
5
C
4
×
10
−
5
C
7
×
10
−
6
C
Validate
Solution:
If
q
is the charge on the ring, then
i
=
q
T
=
q
ω
2
π
Magnetic field,
B
=
µ
0
i
2
R
=
µ
0
(
q
ω
2
π
)
2
R
or
3.8
×
10
−
9
=
(
µ
0
4
π
)
q
ω
R
=
(
10
−
7
)
q
×
40
π
0.10
∴
q
=
3
×
10
−
5
C
© examsnet.com
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