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JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 70
Total: 100
A charge
Q
is uniformly distributed over the surface of non-conducting disc of radius
R
. The disc rotates about an axis perpendicular to its plane and passing through its centre with an angular velocity
ω
. As a result of this rotation a magneticfield of induction
B
is obtained at the centre of the disc. If we keep both the amount of charge placed on the disc and its angular velocity to be constant and vary the radius of the disc then the variation of the magnetic induction at the centreof the disc will be represented by the figure :
[2012]
Validate
Solution:
The magnetic field due to a disc is given as
B
=
µ
0
ω
Q
2
π
R
i.e.,
B
∝
1
R
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