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JEE Main Physics Class 12 Moving Charges and Magnetism Part 1 Questions
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© examsnet.com
Question : 94
Total: 100
Two long conductors, separated by a distance d carry current
I
1
and
I
2
in the same direction. They exert a force
F
on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance is also increased to
3
d
. The new value of the force between them is
[2004]
−
2
F
3
F
3
−
2
F
−
F
3
Validate
Solution:
Force acting between two long conductor carrying current,
F
=
µ
0
4
π
2
I
1
I
2
d
×
l
.....(i)
Where
d
=
distance between the conductors
l
=
length of conductor
In second case,
F
′
=
−
µ
0
4
π
2
(
2
I
1
)
I
2
3
d
l
.....(ii)
From equation (i) and (ii), we have
∴
F
′
F
=
−
2
3
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