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JEE Main Physics Class 12 Moving Charges and Magnetism Part 2 Questions
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© examsnet.com
Question : 19
Total: 100
A massless square loop, of wire of resistance
10
Ω
. supporting a mass of I g. hangs vertically with one of its sides in a uniform magnetic field of
10
3
G
, directed outwards in the shaded region. A dc voltage
V
is applied to the loop. For what value of V. the magnetic force will exactly balance the weight of the supporting mass of
1
g
?
(If sides of the loop
=
10
cm
,
g
=
10
ms
−
2
)
[30-Jan-2023 Shift 1]
1
10
V
100
V
1
V
10
V
Validate
Solution:
F
m
=
mg
∴
ILB
=
mg
∴
(
V
R
)
LB
=
mg
∴
V
=
mgR
LB
=
(
1
×
10
−
3
kg
)
(
10
m
∕
s
2
)
(
10
Ω
)
(
0.1
m
)
(
10
3
×
10
−
4
T
)
=
10
V
© examsnet.com
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