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JEE Main Physics Class 12 Moving Charges and Magnetism Part 2 Questions
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© examsnet.com
Question : 59
Total: 100
A current of
1.5
A
is flowing through a triangle, of side
9
cm
each. The magnetic field at the centroid of the triangle is
(Assume that, the current is flowing in the clockwise direction.)
[31 Aug 2021 Shift 2]
3
×
10
−
7
T
, outside the plane of triangle
2
√
3
×
10
−
7
T
, outside the plane of triangle
2
√
3
×
10
−
5
T
, inside the plane of triangle
3
×
10
−
5
T
, inside the plane of triangle
Validate
Solution:
Given, electric current, I = 1.5 A
Side of triangle,
l
=
9
cm
=
9
×
10
−
2
m
Let OD = OE = OF = r
AD
=
l
2
In
Δ
AOD
,
OD
AD
=
tan
30
°
OD
=
AD
tan
30
°
r
=
OD
=
l
2
×
1
√
3
=
l
2
√
3
Magnetic field due to AB at O,
B
1
=
µ
0
I
4
π
r
[
sin
60
°
+
sin
60
°
]
=
µ
0
I
4
π
r
×
2
√
3
2
⇒
B
1
=
µ
0
d
√
3
4
π
r
(perpendicular inward)
Now, total magnetic field at O due to all sides,
B
=
3
B
1
=
µ
0
4
π
r
3
√
3
By substituting the values, we get
B
=
10
−
7
×
1.5
×
3
√
3
×
2
√
3
9
×
10
−
2
=
3
×
10
−
5
T
(inside the plane of triangle)
© examsnet.com
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