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JEE Main Physics Class 12 Moving Charges and Magnetism Part 3 Questions
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Question : 33
Total: 36
A proton with a kinetic energy of
2.0
eV
moves into a region of uniform magnetic field of magnitude
π
2
×
10
−
3
T
. The angle between the direction of magnetic field and velocity of proton is
60
∘
. The pitch of the helical path taken by the proton is _______
cm
.
(Take, mass of proton
=
1.6
×
10
−
27
kg
and Charge on proton
=
1.6
×
10
−
19
C
) .
[6-Apr-2023 shift 2]
Your Answer:
Validate
Solution:
👈: Video Solution
B
=
π
2
×
10
−
3
K.E.
=
1
2
mV
2
⇒
V
=
√
2
KE
m
PItch
=
v
cos
60
∘
×
time period of one rotation
=
v
cos
60
∘
×
2
π
m
eB
=
√
2
×
2
×
1.6
×
10
−
9
1.6
×
10
−
27
×
cos
60
∘
×
2
π
×
1.6
×
10
−
27
1.6
×
10
−
19
×
π
2
×
10
−
3
=
2
×
10
4
×
1
2
×
4
×
10
−
5
=
4
×
10
−
1
m
=
40
cm
© examsnet.com
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