Focal length of the convex lens, f=0.5m Object is at 2f so, image (I1) will also be at 2f. Image of I1 i.e., I2 will be 1m behind mirror. Now I2 will be object for lens.
∴u=(−1)+(−1)+(−1)=−3m Using lens formula,
1
v
−
1
u
=
1
f
1
v
=
1
f
+
1
u
=
1
+0.5
+
1
−3
or v=
3
5
=0.6m Hence, distance of image from mirror =2+0.6=2.6m and real.