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JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 1 Questions
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© examsnet.com
Question : 17
Total: 99
. A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm.
The distance between an object and the objective lens, atwhich the strain on the eye is minimum is
n
40
cm.
The value of n is ______.
[NA Sep. 05, 2020 (I)]
Your Answer:
Validate
Solution:
Given : Length of compound microscope,
L
=
10
c
m
Focal length of objective
f
0
=
1
c
m
and of eye-piece,
f
e
=
5
c
m
u
0
=
f
e
=
5
c
m
Final image formed at infinity
(
∞
)
,
v
e
=
∞
v
0
=
10
−
5
=
5
Using lens formula,
1
v
−
1
u
=
1
f
1
v
0
−
1
u
0
=
1
f
0
⇒
1
5
−
1
u
0
=
1
1
⇒
u
0
=
−
5
4
c
m
or,
5
4
=
N
40
∴
N
=
200
4
=
50
c
m
© examsnet.com
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