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JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 1 Questions
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Question : 33
Total: 99
An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be :
[8 April 2019 I]
20 cm from the convergent mirror, same size as the object
40 cm from the convergent mirror, same size as the object
40 cm from the convergent lens, twice the size of the object
(Bouns)
Validate
Solution:
v
1
=
40
×
20
(
40
−
20
)
=
40
c
m
u
2
=
60
−
40
=
20
c
m
∴
v
2
=
20
×
10
(
20
−
10
)
=
20
c
m
∴ Image traces back to object itself as image formed by lens is a centre of curvature of mirror.
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