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JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 1 Questions
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© examsnet.com
Question : 50
Total: 99
A hemispherical glass body of radius 10 cm and refractive index 1.5 is silvered on its curved surface. A small air bubble is 6 cm below the flat surface inside it along the axis. The position of the iamge of the air bubble made by the mirror is seen :
[Online April 10, 2016]
14 cm below flat surface
20 cm below flat surface
16 cm below flat surface
30 cm below flat surface
Validate
Solution:
Given, radius of hemispherical glass
R
=
10
c
m
∴
Focal length
f
=
10
2
=
−
5
c
m
u
=
(
10
−
6
)
=
−
4
c
m
By using mirror formula,
1
v
+
1
u
=
1
f
⇒
1
v
+
1
−
4
=
1
−
5
⇒
v
=
20
c
m
Apparent height,
h
a
=
h
r
µ
1
µ
2
=
30
×
1
1.5
=
20
c
m
below flat surface.
© examsnet.com
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