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Test Index
JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 1 Questions
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© examsnet.com
Question : 8
Total: 99
There is a small source of light at some depth below the surface of water (refractive index
=
4
3
) in a tank of large cross sectional surface area. Neglecting any reflection from the bottom and absorption by water, percentage of light that emerges out of surface is (nearly):
[Use the fact that surface area of a spherical cap of height
h
and radius of curvature
r
is
2
π
r
h
]
[9 Jan. 2020 II]
21%
34%
17%
50%
Validate
Solution:
Given,
Refractive index,
µ
=
4
3
4
3
sin
θ
=
1
sin
90
°
⇒
sin
θ
=
3
4
cos
θ
=
√
7
4
Solid angle,
Ω
=
2
π
(
1
−
cos
θ
)
=
2
π
(
1
−
√
7
∕
4
)
Fraction of energy transmitted
=
2
π
(
1
−
cos
θ
)
4
π
=
1
−
√
7
∕
4
2
=
0.17
Percentage of light emerges out of surface
=
0.17
×
100
=
17
%
© examsnet.com
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