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JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 2 Questions
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© examsnet.com
Question : 15
Total: 112
A biconvex lens of refractive index 1.5 has a focal length of
20
cm
in air. Its focal length when immersed in a liquid of refractive index 1.6 will be:
[29-Jan-2024 Shift 1]
−
16
cm
−
160
cm
+
160
cm
+
16
cm
Validate
Solution:
👈: Video Solution
µ
1
=
1.5
µ
m
=
1.6
f
a
=
20
cm
As
f
m
f
a
=
(
µ
1
−
1
)
µ
m
(
µ
1
−
µ
m
)
f
m
20
=
(
1.5
−
1
)
1.6
(
1.5
−
1.6
)
f
m
=
−
160
cm
© examsnet.com
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