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JEE Main Physics Class 12 Ray Optics and Optical Instruments Part 2 Questions
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© examsnet.com
Question : 57
Total: 112
For an object placed at a distance
2.4
m
from a lens, a sharp focused image is observed on a screen placed at a distance
12
c
m
from the lens. A glass plate of refractive index
1.5
and thickness
1
c
m
is introduced between lens and screen such that the glass plate plane faces parallel to the screen. By what distance should the object be shifted so that a sharp focused image is observed again on the screen?
[25-Jul-2022-Shift-2]
0.8
m
3.2
m
1.2
m
5.6
m
Validate
Solution:
The shift produced by the glass plate is
d
=
t
(
1
−
1
µ
)
=
1
×
(
1
−
1
1.5
)
=
1
3
c
m
So final image must be produced at
(
12
−
1
3
)
c
m
=
35
3
c
m
from lens so that glass plate must shift it to produce image at screen. So
1
12
−
1
−
240
=
1
f
=
1
35
∕
3
−
1
u
1
u
=
3
35
−
1
12
−
1
240
or
u
=
−
560
c
m
so
shift
=
5.6
−
2.4
=
3.2
m
© examsnet.com
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