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JEE Main Physics Class 12 Wave Optics Part 1 Questions
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Question : 22
Total: 100
In a Young’s double slit experiment 15 fringes are observed on a small portion of the screen when light of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when another light source of wavelength λ is used. Then the value of λ is (in nm) ______.
[NA 9 Jan 2020 II]
Your Answer:
Validate
Solution:
Fringe width,
β
=
λ
D
d
where,
λ
=
wavelength,
D
=
distance of screen from slits,
d
=
distance between slits
ATQ
15
×
λ
1
D
d
=
10
×
λ
2
D
d
⇒
15
λ
1
=
10
λ
2
⇒
λ
2
=
1.5
λ
1
15
λ
1
=
1.5
×
500
n
m
⇒
λ
2
=
750
n
m
© examsnet.com
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