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JEE Main Physics Class 12 Wave Optics Part 1 Questions
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© examsnet.com
Question : 30
Total: 100
In an interference experiment the ratio of amplitudes of coherent waves is
a
1
a
2
=
1
3
.
The ratio of maximum and minimum intensities of fringes will be :
[8 April 2019 I]
2
18
4
9
Validate
Solution:
Given amplitude ratio of waves is
a
1
a
2
=
3
1
so,
I
max
I
min
−
(
a
2
+
a
1
a
2
−
a
1
)
2
=
(
a
2
a
1
+
1
a
2
a
1
−
1
)
2
=
(
3
+
1
3
−
1
)
2
=
(
4
2
)
2
=
4
1
=
4
© examsnet.com
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