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JEE Main Physics Class 12 Wave Optics Part 1 Questions
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© examsnet.com
Question : 34
Total: 100
In a Young's double slit experiment with slit separation
0.1
m
m
,
one observes a bright fringe at angle
1
40
r
a
d
by using light of wavelength
λ
1
When the light of wavelength
λ
2
is used a bright fringe is seen at the same angle in the same set up. Given that
λ
1
and
λ
2
are in visible range
(
380
n
m
to
740
n
m
)
, their values are:
[10 Jan. 2019 I]
625 nm, 500 nm
380 nm, 525 nm
380 nm, 500 nm
400 nm, 500 nm
Validate
Solution:
Path difference
=
d
sin
θ
≈
d
θ
=
0.1
×
1
40
m
m
=
2500
n
m
For bright fringe, path difference must be integral multiple of
λ
.
∴
2500
=
n
λ
1
=
m
λ
2
∴
λ
1
=
625
(
for
n
=
4
)
,
λ
2
=
500
(
for
m
=
5
)
© examsnet.com
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