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JEE Main Physics Class 12 Wave Optics Part 1 Questions
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Question : 43
Total: 100
The angular width of the central maximum in a single slit diffraction pattern is 60°. The width of the slit is 1 µm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young's fringes can be observed on a screen placed at a distance 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance?
(i.e. distance between the centres of each slit.)
[2018]
25 µm
50 µm
75 µm
100 µm
Validate
Solution:
Angular width of central maxima
=
2
λ
d
or,
λ
=
d
2
;
Fringe width,
β
=
λ
×
D
d
′
10
−
2
=
d
2
×
50
×
10
−
2
d
′
=
10
−
6
×
50
×
10
−
2
2
×
d
′
Therefore, slit separation distance,
d
′
=
25
µ
m
© examsnet.com
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