C : H = 4 : 1 C : O = 3 : 4 Mass ratio C : H : O = 12 : 3 : 16 Mole ratio C : H : O = 1 : 3 : 1 Empirical formula = CH3O Molecular formula =C2H6O2 (saturated acyclic organic compound) C2H6O2+
5
2
O2────▸2CO2+3H2O 2‌mole‌‌‌‌‌‌5‌mol Moles of O2 required = 5 moles
