JEE Mains 04-Sep-2020 Shift 2 Solved Paper

(I) Adiabatic process ⇒ΔQ=0
No exchange of heat takes place with surroundings
(II) Isothermal proess ⇒ Temperature remains constant (ΔT=0)
Δu=

F

2

nRΔT⇒Δu=0
No change in internal energy [Δu=0]
(III) Isochoric process Volume remains constant
ΔV=0
W=∫P.dV=0
Hence work done is zero.
(IV) Isobaric process ⇒ Pressure remains constant
W=P.ΔV≠0
Δu=

F

2

nRΔT =

F

2

[PΔV]≠0
ΔQ=nCpΔT≠0