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JEE Mains 1-Feb-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 30
Total: 90
A series LCR circuit is connected to an ac source of
220
V
,
50
Hz
. The circuit contain a resistance
R
=
100
Ω
and an inductor of inductive reactance
X
L
=
79.6
Ω
. The capacitance of the capacitor needed to maximize the average rate at which energy is supplied will be _______
µ
F
.
[1-Feb-2023 Shift 1]
Your Answer:
Validate
Solution:
To maximize the average rate at which energy supplied i.e. power will be maximum.
So in LCR circuit power will be maximum at the condition of resonance and in resonance condition
X
L
=
X
C
79.6
=
1
ω
C
∴
C
=
1
2
π
×
50
×
79.6
∴
C
=
40
µ
F
© examsnet.com
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