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JEE Mains 1-Feb-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 7
Total: 90
'
n
' polarizing sheets are arranged such that each makes an angle
45
∘
with the proceeding sheet. An unpolarized light of intensity
I
is incident into this arrangement. The output intensity is found to be
I
64
. The value of
n
will be:
[1-Feb-2023 Shift 1]
3
6
5
4
Validate
Solution:
After passing through first sheet
I
1
=
I
2
After passing through second sheet
I
2
=
I
1
cos
2
(
45
∘
)
=
I
4
After passing through
n
th
sheet
I
n
=
I
2
n
=
I
64
n
=
6
© examsnet.com
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