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JEE Mains 1-Feb-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 21
Total: 90
For a train engine moving with speed of
20
ms
−
1
. the driver must apply brakes at a distance of
500
m
before the station for the train to come to rest at the station. If the brakes were applied at half of this distance, the train engine would cross the station with speed
√
x
ms
−
1
. The value of
x
is _______
(Assuming same retardation is produced by brakes)
[1-Feb-2023 Shift 2]
Your Answer:
Validate
Solution:
u
=
20
m
∕
s
,
S
1
=
500
m
,
v
=
0
By third equation of mation
0
=
(
20
)
2
−
2
a
.500
⇒
a
=
4
10
m
∕
s
2
u
=
20
m
∕
s
,
S
2
=
250
m
,
v
=
?
v
2
=
(
20
)
2
−
2
a
.250
=
v
=
√
200
m
∕
s
x
=
200
© examsnet.com
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